若2x-y=0,求代数式[(x^2+y^2)-(x-y)^2+2y×(x-y)]÷4y的值
问题描述:
若2x-y=0,求代数式[(x^2+y^2)-(x-y)^2+2y×(x-y)]÷4y的值
答
原式 = (X² + Y² - X² +2XY - Y²+ 2XY - 2Y²)/ 4Y
= (4XY - 2Y²)/ 4Y
= (2X - Y)/ 2
= 0