1.(x/2+20)/(x/3)=(x/2-20)/(x/4)

问题描述:

1.(x/2+20)/(x/3)=(x/2-20)/(x/4)

.(x/2+20)/(x/3)=(x/2-20)/(x/4)
x/3*(x/2-20)=x/4*(x/2+20)
4(x/2-20)=3*(x/2+20)
2x-80=1.5x+60
2x-1.5x=60+80
0.5x=140
x=280

(x/2+20)/(x/3)=(x/2-20)/(x/4)
方程两边同时乘以12x得
4(x/2+20)=3(x/2-20)
4(x+40)=3(x-40)
4x+160=3x-120
x=-280