当X=0.68,y=-0.96时,求多项式12X^3-3x^3*y+2x^2y-10x^3+3x^3y-2x^2y-2x^3+10的值.kkkkkkkkk
问题描述:
当X=0.68,y=-0.96时,求多项式12X^3-3x^3*y+2x^2y-10x^3+3x^3y-2x^2y-2x^3+10的值.
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答
当X=0.68,y=-0.96时,求多项式12X^3-3x^3*y+2x^2y-10x^3+3x^3y-2x^2y-2x^3+10的值.
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