k为何值时,不等式1/2(kx+8)>3恒成立wo 要过程``````````````````````````````````````````````````````````````````````````````````````````````````````````````````````````````````````````````````````````````````````````````````````````````````````````````````````````````````````gogo加油
问题描述：
k为何值时,不等式1/2(kx+8)>3恒成立
wo 要过程``````````````````````````````````````````````````````````````````````````````````````````````````````````````````````````````````````````````````````````````````````````````````````````````````````````````````````````````````````gogo加油
答
化 简 一 下
1 / 2 k x + 1 > 0
就 可 看 出 k = 0恒成立