求大神解个二元一次方程组!{1800x+2500y=590000{2000x+2800y=660000
问题描述:
求大神解个二元一次方程组!
{1800x+2500y=590000
{2000x+2800y=660000
答
x=(590000-2500y)/1800=(660000-2800y)/2000
(590000-2500y)*2000=(660000-2800y)*1800
1180000000-5000000y=1188000000-5040000y
5040000y-5000000y=1188000000-1180000000
40000y=8000000
y=200
代入上式求x不用再细解了吧