初一下学期二元一次方程难题,已知x^2m-n×y^3m和4x^2n×y^5+2n是同类项,则m^n与n^m的大小关系是____?
问题描述:
初一下学期二元一次方程难题,
已知x^2m-n×y^3m和4x^2n×y^5+2n是同类项,则m^n与n^m的大小关系是____?
答
2m=2n
3m=5...
答
因为 x^2m-n×y^3m和4x^2n×y^5+2n是同类项,则
2m - n = 2n
3m = 5 + 2n
解得,m = 3,n = 2
m^n = 3^2 = 9,n^m = 2^3 = 8
所以,m^n与 > n^m