3,8,12,10,将每个数只用一次进行加减乘除混合运算怎样等于24

问题描述:

3,8,12,10,将每个数只用一次进行加减乘除混合运算怎样等于24

10÷(8-3)x12=24

1: (10 ÷ (8 - 3)) × 12
2: 10 ÷ (8 - 3) × 12
3: 10 ÷ ((8 - 3) ÷ 12)
4: 10 × (12 ÷ (8 - 3))
5: 10 × 12 ÷(8 - 3)
6: (10 × 12) ÷ (8 - 3)
7: (12 ÷ (8 - 3)) × 10
8: 12 ÷ (8 - 3) × 10
9: 12 ÷ ((8 - 3) ÷ 10)
10: 12 × (10 ÷ (8 - 3))
11: 12 × 10 ÷(8 - 3)
12: (12 × 10) ÷ (8 - 3)

(10 ÷ (8 - 3)) × 12
10 ÷ (8 - 3) × 12
10 ÷ ((8 - 3) ÷ 12)
10 × (12 ÷ (8 - 3))
10 × 12 ÷(8 - 3)
(10 × 12) ÷ (8 - 3)
12 ÷ (8 - 3) × 10
12 ÷ ((8 - 3) ÷ 10)
12 × (10 ÷ (8 - 3))
12 × 10 ÷(8 - 3)
(12 × 10) ÷ (8 - 3)

1: (10 ÷ (8 - 3)) × 12
2: 10 ÷ (8 - 3) × 12
3: 10 ÷ ((8 - 3) ÷ 12)
4: 10 × (12 ÷ (8 - 3))
5: 10 × 12 ÷(8 - 3)
6: (10 × 12) ÷ (8 - 3)
7: (12 ÷ (8 - 3)) × 10
8: 12 ÷ (8 - 3) × 10

(10×12)÷(8-3)=24