x的平方-9分之6+x+3分之1=多少?
问题描述：
x的平方-9分之6+x+3分之1=多少?
答
x^2-6x/9+1/3=x^2-2x/3+(1/3)^2+1/3-1/9=(x-1/3)^2+2/9
只能写到这了，这是最简化结果
答
x的平方-9分之6+x+3分之1
=（6+x-3)/(x-3)(x+3)
=（x+3)/(x-3)(x+3)
=1/(x-3)
答
原式=6/(x+3)(x-3)+(x-3)/(x+3)(x-3)
=(6+x-3)/(x+3)(x-3)
=(x+3)/(x+3)(x-3)
=1/(x-3)