如果(2x+2y+1)(2x+2y-1)=31,则(X+Y)^2=
问题描述：
如果(2x+2y+1)(2x+2y-1)=31,则(X+Y)^2=
答
(2x+2y+1)(2x+2y-1)=31
(2x+2y)²-1=31
(2x+2y)²=32
4(x+y)²=32
(x+y)²=8
答
(2x+2y+1)(2x+2y-1)=31
[2(x+y)]^2-1=31
(x+y)^2=32/4=8
答
(2x+2y+1)(2x+2y-1)=31
（2x+2y）^2=30
4(X+Y)^2=30
(X+Y)^2=8
答
(2x+2y+1)(2x+2y-1)=31
(2x+2y)^2-1=31
(2x+2y)^2=32
4(x+y)^2=32
(x+y)^2=8
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答
(2x+2y+1)(2x+2y-1)=31
[2(x+y)+1][2(x+y)-1]=31
4(x+y)²-1=31
4(x+y)²=32
(x+y)²=8
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