数学简算题:(41/12-10/7)-(18/7-19/12)

问题描述:

数学简算题:(41/12-10/7)-(18/7-19/12)

41/12+19/12-(10/7+18/7)=5-4=1

(41/12-10/7)-(18/7-19/12)
=41/12-10/7-18/7+19/12
=(41/12+19/12)-(10/7+18/7)
=60/12-28/7
=5-4
=1

(41/12-10/7)-(18/7-19/12)
=41/12-10/7-18/7+19/12
=41/12+19/12-(10/7+18/7)
=60/12-28/7
=5-4
=1