-8x^2y^4*3x/4y^6/(-x^2y/6z)
问题描述:
-8x^2y^4*3x/4y^6/(-x^2y/6z)
答
x^2+x-1=0
x^2=-x+1
所以x^3=x^2*x=(-x+1)*x=-x^2+x=-(-x+1)+x=2x-1
所以x^3+2x^2-7=(2x-1)+2(-x+1)-7=2x-1-2x+2-7=-6 x^2+x-1=0
x^2=-x+1
所以x^3=x^2*x=(-x+1)*x=-x^2+x=-(-x+1)+x=2x-1
所以x^3+2x^2-7=(2x-1)+2(-x+1)-7=2x-1-2x+2-7=-6
答
-8x^2y^4*3x/4y^6/(-x^2y/6z)
=-8x^2y^4*(3x/4y^6)*(-6z/x^2y)
=8*6x^2y^4*3x*6z/(4y^6*x^2y)
=144x^3y^4z/(4x^2y^7)
=36xz/y^3