若1+tanx|1-tanx=2008,则1|cos2x+tan2x=?2.已知sinx+siny=sin225,cosx+cosy=cos225,求cos(x-y)的值
问题描述:
若1+tanx|1-tanx=2008,则1|cos2x+tan2x=?
2.已知sinx+siny=sin225,cosx+cosy=cos225,求cos(x-y)的值
答
若1+tanx|1-tanx=2008,则1|cos2x+tan2x=?
2.已知sinx+siny=sin225,cosx+cosy=cos225,求cos(x-y)的值