x*x+y*y+4x-6y+13=0求xy=?

问题描述:

x*x+y*y+4x-6y+13=0求xy=?

x²+y²+4x-6y+13=0
(x²+4x+4)+(y²-6y+9)=0
(x+2)²+(y-3)²=0
所以x+2=0,y-3=0
x=-2,y=3
所以xy=-6