求一元二次方程因式分解!
问题描述：
求一元二次方程因式分解!
3X^2-12X=-12
3X(X -1)=2(X-1)
(2X-1)^2=(3-X)^2
答
3X^2-12X=-12 3X^2-12X+12 =0x^2-4x+4=0(x-2)^2=0x1=x2=23X(X -1)=2(X-1)3X(X -1)-2(X-1)=0(x-1)(3x-2)=0x1=1x2=2/5(2X-1)^2=(3-X)^2 (2X-1)^2-(3-X)^2 =0(2x-1+3-x)(2x-1-3+x)=0(x+2)(3x-4)=0x1=-2x2=4/3