计算.2\1x3+2\3x5+2\5x7+...+2\2007X2009
问题描述:
计算.2\1x3+2\3x5+2\5x7+...+2\2007X2009
答
裂项求和法因为1/〔n(n+2)〕=1/2〔1/n-1/(n+2)〕所以原式=1-1/3+1/3-1/5+……+1/2007-1/2009=2008/2009
计算.2\1x3+2\3x5+2\5x7+...+2\2007X2009
裂项求和法因为1/〔n(n+2)〕=1/2〔1/n-1/(n+2)〕所以原式=1-1/3+1/3-1/5+……+1/2007-1/2009=2008/2009