计算：8^(1-log(83))
问题描述：
计算：8^(1-log(83))
(27^(2/3))-log(32)
答
8^(1-log(8,3))
=8^1÷8^log(83)
=8/3(27^(2/3))-log(32)这题也帮忙算下，谢了(27^(2/3))-log(32)=(3³)^2/3-log(3,2)=3²-log(3,2)=9-log(3,2)