计算题:(a-b+c)(b-a+c)= (2a-b-c)^2= (a-3)(a^2+9)(a+3)=
问题描述:
计算题:(a-b+c)(b-a+c)= (2a-b-c)^2= (a-3)(a^2+9)(a+3)=
是:(a-b+c)(b-a+c)=
(2a-b-c)^2=
(a-3)(a^2+9)(a+3)=
答
(a-b+c)(b-a+c)=[c+(a-b)][c-(a-b)]=c^2-(a-b)^2=c^2-(a^2-2ab+b^2)=c^2-a^2+2ab-b^2(2a-b-c)^2=(2a)^2+b^2+c^2-2*2a*b-2*2a*c+2bc=4a^2+b^2+c^2-4ab-4ac+2bc(a-3)(a^2+9)(a+3)=(a-3)(a+3)(a^2+9)=(a^2-9)(a^2+9)=...在帮我解两个好吗?(7x-y)(-7x+y)=(-3m-n)(3m+2n)=谢谢~(7x-y)(-7x+y)=-(7x-y)(7x-y)=-(7x-y)^2=-(49x^2-14xy+y^2)=-49x^2+14xy-y^2(-3m-n)(3m+2n)=-(3m+n)(3m+2n)=-(3m+2n)^2=-(9m^2+12mn+4n^2)=-9m^2-12mn-4n^2提示:运用完全平方公式