已知z=(1+根号3i/1-根号3i)^2,求|z|
问题描述:
已知z=(1+根号3i/1-根号3i)^2,求|z|
答
z=(1+根号3i/1-根号3i)^2
z=(1+√3i/1-√3i)^2={(1+√3i)*(1+√3i)/【(1-√3i)*(1+√3i)】}^2=(-1/2+√3i)^2=-1/2-√3i/2
|z| =1