将(2x^2+2x+13)/(x^5-2x^4+2x^3-4x^2+x-2)分解成部分分式之和

x^5-2X^4+2x^3-4x^2+x-2=x^4(x-2)+2x^2(x-2)+(x-2)=(x^4+2x^2+1)(x-2)=[(x^2+1)^2(x-2)]so原式=[2（x^2+1）+2(x-2)+15]/[(x^2+1)^2(x-2)]=2/[(x^2+1)(x-2)]+2/(x^2+1)^2+15/[(x^2+1)^2(x-2)]额,大概就是这样了,你再...