已知弧长=63.015m;玄长=62.971m;求半径?那位老师知道的告诉下,顺便把公式也告诉我,

问题描述:

已知弧长=63.015m;玄长=62.971m;求半径?那位老师知道的告诉下,顺便把公式也告诉我,

已知弧长C=63.015m;玄长L=62.971m;求半径R?
Rn+1=(1+(L-2*Rn*SIN(C/(2*Rn)))/(L-C*COS(C/(2*Rn))))*Rn
R0=400
R1=455.867
R2=482.244
R3=486.635
R4=486.737
R5=486.738
R6=486.738
R=486.738m