-6abc-{2a^2b-2[3abc-(ab^2c-a^2b)]},其中abc满足条件ax^b+2y^3+2xy^c=0
问题描述:
-6abc-{2a^2b-2[3abc-(ab^2c-a^2b)]},其中abc满足条件ax^b+2y^3+2xy^c=0
答
原式=1/2a²b-(3/2a²b-6abc+2a²c-4a²c)-3abc
=1/2a²b-3/2a²b+6abc-2a²c+4a²c-3abc
=(1/2a²b-3/2a²b)+(6abc-3abc)+(-2a²c+4a²c)
=-a²b+3abc+2a²c
当a=-1, b=-3, c=1/2时
原式=-(-1)²×(-3)+3×(-1)×(-3)×1/2+2×(-1)²×1/2
=-1×(-3)+3×(-1)×(-3)×1/2+2×1×1/2
=3+9/2+1
=17/2