急需求解三角方程arctg(0.2x)+arctg(0.025x)-arctg(0.005x)-arctg(0.001x)=π^2
问题描述:
急需求解三角方程arctg(0.2x)+arctg(0.025x)-arctg(0.005x)-arctg(0.001x)=π^2
答
>>solve('arctan(0.2*x)+arctan(0.025*x)-arctan(0.005*x)-arctan(0.001*x)=(pi)^2')Warning: Explicit solution could not be found.> In solve at 140 ans = [ empty sym ] 无解