已知8^x+1&2^x+2=32 x=?
问题描述：
已知8^x+1&2^x+2=32 x=?
答
“1&2^x 8的x+1次方除以2的x+2次方等于32求x[8^(x+1)]/[2^(x+2)]=32[2^(3x+3)]/[2^(x+2)]=2^52^[(3x+3)-(x+2)]=2^52^(2x+1)=2^52x+1=52x=4x=2
已知8^x+1&2^x+2=32 x=?
“1&2^x 8的x+1次方除以2的x+2次方等于32求x[8^(x+1)]/[2^(x+2)]=32[2^(3x+3)]/[2^(x+2)]=2^52^[(3x+3)-(x+2)]=2^52^(2x+1)=2^52x+1=52x=4x=2