设f(x)=ax7-bx+2,且f(-5)=17,则f(5)=_.

问题描述:

设f(x)=ax7-bx+2,且f(-5)=17,则f(5)=______.

因为f(x)=ax7-bx+2,函数y=ax7-bx,是奇函数,因为f(-5)=17=-ax7+bx+2,
所以f(5)=ax7-bx+2=-15+2=-13
故答案为:-13.