解方程:(2x+3)+(x-7)(x+6)=x²-10解方程:x(2x+3)+(x-7)(x+6)=x²-10

问题描述:

解方程:(2x+3)+(x-7)(x+6)=x²-10
解方程:x(2x+3)+(x-7)(x+6)=x²-10

29

2x+3+x*2+6x-7x-42=x*2-10
x-39+10=0
x=29

(2x+3)+(x-7)(x+6)=x²-10
2X + 3 + X ² - 7X + 6X - 42 = X² -10
X = 42-10-3
X = 29

(2x+3)+(x-7)(x+6)=x²-10
2x+3+x²-x+42=x²-10
x+45=-10
x=-45-10
x=-55