物理核质比公式q/m=?（已知加速电压u1偏向电压u2两电极板间距d磁感应强度B）

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What is the value of q/m for a particle that moves in a circle of radius 6.2 mm in a 0.56 T magnetic field if?
What is the value of q/m for a particle that moves in a circle of radius 6.2 mm in a 0.56 T magnetic field if a crossed 220 V/m electric field will make the path straight?
Best Answer -
B .q.v = E .q
v = E / B
B .q .v = m .v^2 / R
v / R .B = q / m
q / m = E / B^2 .R = 220 / 0.56^2 .6.2 .10^–3
q / m = 1.13 .10^5 C/kg