(1+i)/(1-i)^2008等于
问题描述：
(1+i)/(1-i)^2008等于
答
(1＋i)/(1－i)=(1＋i)²/(1＋1)=i,所以[(1＋i)/(1－i)]^2008=i^1004=1
(1+i)/(1-i)^2008等于
(1＋i)/(1－i)=(1＋i)²/(1＋1)=i,所以[(1＋i)/(1－i)]^2008=i^1004=1