|-3-x+y |+(4x+3y-2)的二次方等于零
问题描述：
|-3-x+y |+(4x+3y-2)的二次方等于零
答
因为|-3-x+y |>=0,(4x+3y-2)^2>=0 而|-3-x+y |+(4x+3y-2)^2=0 所以|-3-x+y |=0,(4x+3y-2)^2=0 即-3-x+y=0,4x+3y-2=0 解得x=-1,y=2