逻辑函数Y=A+(B+C')'(A+B'+C)(A+B+C),希望马上可以有人给答案

Y=A+(B+C')'(A+B'+C)(A+B+C)
=A+(B'C)(A+B'+C)(A+B+C)
=A+(B'C)[(A+C)+(A+C)B'+(A+C)B+B'B]
=A+(B'C)(A+C)
=A+AB'C+B'C
=A+B'C谢谢！真是高手！还有这个：Y=BC'+ABC'E+B'(A'D'+AD)'+B(AD'+A'D)望解答！Y=BC'+ABC'E+B'(A'D'+AD)'+B(AD'+A'D) =BC'+B'(A'D')'(AD)'+BAD'+BA'D =BC'+B'(A+D)(A'+D')+BAD'+BA'D =BC'+B'(AD'+A'D)+BAD'+BA'D =BC'+BAD'+BA'D