-5X3+2X4+3X2+X-1=0,求X (负5X的3次方加上2X的4次方加上3X的平方加上再减1
问题描述:
-5X3+2X4+3X2+X-1=0,求X (负5X的3次方加上2X的4次方加上3X的平方加上再减1
答
-5x³+2x^4+3x²+x-1=02x^4-2x³-3x³3x²+x-1=02x³(x-1)-3x²(x-1)+(x-1) = 0(x-1)(2x³-3x²+1) = 0(x-1)(2x³-2x²-x²+1) = 0(x-1){2x²(x-1)-(x+1)(x-1)...