x-3/2x+1=1 x-2/6-x+2=x-1/2+1 0.2x+0.5/0.5-0.03+0.02x/0.03=x-5/2
问题描述:
x-3/2x+1=1 x-2/6-x+2=x-1/2+1 0.2x+0.5/0.5-0.03+0.02x/0.03=x-5/2
答
x-3/2x+1=1
x-3=2x+1
x-2x=1+3
x=-4
x-2/6-x+2=x-1/2+1
x-2-6(x+2)=3(x-1)+6
x-2-6x-12=3x-3+6
-5x-3x=3+14
-8x=17
x=-17/8
0.2x+0.5/0.5-0.03+0.02x/0.03=x-5/2
(2x+5)/5-(3+2x)/3=(x-5)/2
6(2x+5)-10(3+2x)=15(x-5)
12x+30-30-20x=15x-75
-8x-15x=-75
-23x=-75
x=75/23