怎么算(3a-b+1)(3a+b-1)?和1/6X-4Y-1/6X+4Y-3X/4Y'-9X'
问题描述:
怎么算(3a-b+1)(3a+b-1)?和1/6X-4Y-1/6X+4Y-3X/4Y'-9X'
答
(3a-b+1)(3a+b+1)=[(3a+1)-b][(3a+1)+b]=(3a+1)^2-b^2=9a^2+6a+1-b^2
1/6X-4Y-1/6X+4Y-3X/4Y'-9X'=1/6X-1/6X-4Y+4Y-3X/4Y'-9X'=-3X/4Y'-9X