a,b,c,d叫做二阶行列式,算法ad-bc,请你计算a+1,a-1,a-2,a+2=
问题描述：
a,b,c,d叫做二阶行列式,算法ad-bc,请你计算a+1,a-1,a-2,a+2=
答
=(a+1)(a+2)-(a-1)(a-2)=a^2+3a+2-a^2+3a-2=6a
a,b,c,d叫做二阶行列式,算法ad-bc,请你计算a+1,a-1,a-2,a+2=
=(a+1)(a+2)-(a-1)(a-2)=a^2+3a+2-a^2+3a-2=6a