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(3a^2-15a+21)/(a^2-5a+6)-(2a^2-6a+1)/(a^2-3a+2)

分类: 作业答案 • 2022-01-17 17:10:30
问题描述：

(3a^2-15a+21)/(a^2-5a+6)-(2a^2-6a+1)/(a^2-3a+2)

答

(3a^2-15a+21)/(a^2-5a+6)-(2a^2-6a+1)/(a^2-3a+2)
=(3a^2-15a+21)/(a-2)(a-3)-(2a^2-6a+1)/(a-2)(a-1)
=[(3a^2-15a+21)(a-1)-(2a^2-6a+1)(a-3)]/(a-1)(a-2)(a-3)
=[(3a^3-18a^2+36a-21)-(2a^3-12a^2+19a-3)]/(a-1)(a-2)(a-3)
=(a^3-6a^2+17a-18)/(a-1)(a-2)(a-3)
=(a-2)(a^2-4a+9)/(a-1)(a-2)(a-3)
=(a^2-4a+9)/(a-1)(a-3)

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