若x∈ [-π/3,π/4],求函数y=sec^ 2x+2tanx+1的最值及相应的x值
问题描述:
若x∈ [-π/3,π/4],求函数y=sec^ 2x+2tanx+1的最值及相应的x值
答
y=tan²x+1+2tanx+1
=(tanx+1)²+1
-π/3