若x∈ [-π/3,π/4],求函数y=sec^ 2x+2tanx+1的最值及相应的x值

问题描述:

若x∈ [-π/3,π/4],求函数y=sec^ 2x+2tanx+1的最值及相应的x值

y=tan²x+1+2tanx+1
=(tanx+1)²+1
-π/3