(-√3/2-1/2i)^12+[ (2+2i)/(1-√3i) ]^8
问题描述：
(-√3/2-1/2i)^12+[ (2+2i)/(1-√3i) ]^8
√3是根号3
答
-√3/2-1/2i=cos(-2π/3)+isin(-2π/3)(2+2i)/(1-√3i)=2√2(cosπ/4+isinπ/4)/2[cos(-π/3)+isin(-π/3)]所以(-√3/2-1/2i)^12+[ (2+2i)/(1-√3i) ]^8=[cos(-2π/3)+isin(-2π/3)]^12+[2√2(cosπ/4+isinπ/4)/2[c...