x²-x-2=0求(x²-x)²-1+根号3分之x²-x+2被根号3的值
问题描述:
x²-x-2=0求(x²-x)²-1+根号3分之x²-x+2被根号3的值
答
x²-x-2=0
x²-x=2
(x²-x)²-(x²-x+2√3)/(1+√3)
=2²-(2+2√3)/(1+√3)
=4-2
=2