弧两点直线距离16米,4米,因圆心被挡画不出弧,求给个画法,给个图样,
问题描述:
弧两点直线距离16米,4米,因圆心被挡画不出弧,求给个画法,给个图样,
答
弧两点直线距离L=16米,弧高H=2.4米,求弧半径R和弧长C?弧所对的圆心角为A.R^2=(R-H)^2+(L/2)^2R^2=R^2-2*R*H+H^2+L^2/42*R*H=H^2+L^2/4R=H/2+L^2/(8*H) =2.4/2+16^2/(8*2.4)=14.533米A=2*ARC SIN((L/2)/R)=2*ARC SIN(...