高中生物1/3PPgg×2/3Ppgg个体自交,后代出现杂合子概率为2/3×1/2,概率是怎么算的?

问题描述:

高中生物1/3PPgg×2/3Ppgg个体自交,后代出现杂合子概率为2/3×1/2,概率是怎么算的?

1/3PPgg自交后杂合子概率为0,2/3Ppgg自交,会出现1/2Ppgg和1/4PPgg,1/4ppgg,所以杂合子只有Ppgg,概率为2/3×1/2