【sin(α+2kπ)+cos(π/2+α)+tan(3π-α)】/【sin(α-π)+cos(α-π/2)+cot(π/2-α)】

问题描述:

【sin(α+2kπ)+cos(π/2+α)+tan(3π-α)】/【sin(α-π)+cos(α-π/2)+cot(π/2-α)】

【sin(α+2kπ)+cos(π/2+α)+tan(3π-α)】/【sin(α-π)+cos(α-π/2)+cot(π/2-α)】
=(sina-sina-tana)/(-sina+sina+tana)=-1