计算：(1-√3i)(cosx+isinx)÷(1-i)(cosx-isinx),也是一个复数的问题.求解答QAQ

[(1-√3i)(cosx+isinx)]÷(1-i)(cosx-isinx)=[2(1/2-√3/2*i)(cosx+isinx)]÷[√2(√2/2-√2/2*i)][cos(-x)+isin(-x)]=[2(cos5π/3+isin5π/3)*(cosx+isinx)]÷[√2(cos7π/4+isin7π/4)]*[(cos(-x)+isin(-x))]=√2[...