溶度积与溶解度的换算题对于Ag2CrO4,S=0.00445g,求Ksp请问如何计算?麻烦给个过程,

溶解度 S=0.00445 g/100 mL (题目单位不对?!）==》 S=0.0445 g/L ==>0.0445/331.73 mol/L = 1.34 x10^-4 mol/L因为,Ag2CrO4 ---> 2Ag+ + CrO42-[Ag+]= 2S=2.68x10^-4,[CrO42-]=S=1.34x10^-4Ksp=[Ag+]^2[CrO42-]=9.66...