2n-(4n^2-kn+3)^0.5的极限是1,则k的值等于?
问题描述：
2n-(4n^2-kn+3)^0.5的极限是1,则k的值等于?
答
2n-根号(4n^2-kn+3)=根号(4n^2)-根号(4n^2-kn+3)=4n^2-(4n^2-kn+3)--------------------------------= （上下同时乘以根号(4n^2)+根号(4n^2+kn+3)）根号(4n^2)+根号(4n^2-kn+3)kn-3--------------------------------...