sin29/6π+COS(-29/3π)+tan(-25/4π)答案拜托了各位

问题描述:

sin29/6π+COS(-29/3π)+tan(-25/4π)答案拜托了各位

=sin(24/6+5/6)π+cos(-30/3+1/3)π+tan(-24/4-1/4)π =sin(5/6π)+cos1/3π-tan1/4π =1/2+1/2-1 =0