60.Fe2+ + 2e¯ ---> Fe(s) E° = - 0.44 volt

60.Fe2+ + 2e¯ ---> Fe(s) E° = - 0.44 volt
Ni2+ + 2e¯ ---> Ni(s) E° = - 0.23 volt
The standard reduction potentials for two half reactions are given above.The Nernst equation
for a galvanic cell at 25°C in which Fe(s) reduces Ni2+ is the following.
E = E° - 0.059/2 log [Fe2+] / [Ni2+]
What is the equilibrium constant for the reaction below?
Fe(s) + Ni2+ ---> Fe2+ + Ni(s)
A) 1.9 x 10¯ 23 B) 7.6 x 10¯ 8 C) 3.6 x 10+3 D) 1.3 x 10+7 E) 5.2 x 10+22