已知函数f（x）=2√3sinxcosx+2（cosx）平方-1,g（x）=｜f（x）｜,求函数g（x）的单调递减区间,需要转
问题描述：
已知函数f（x）=2√3sinxcosx+2（cosx）平方-1,g（x）=｜f（x）｜,求函数g（x）的单调递减区间,需要转
需要转换过程
答
f(x) = 2√3sinxcosx + 2cos^2x-1
= √3sin2x + cos2x
= 2(sin2xcosπ/6+cos2xsinπ/6)
= 2sin(2x+π/6)
g(x) = | f(x) | = 2 | sin(2x+π/6) |
x∈【kπ-7π/12,kπ-π/12】时,2x+π/6∈【2kπ-π,2kπ】,g(x) = -2 sin(2x+π/6)
x∈【kπ-π/12,kπ+5π/12】时,2x+π/6∈【2kπ,2kπ+π】,g(x) =2 sin(2x+π/6)
2x+π/6 ∈（2kπ-π/2,2kπ）,（2kπ+π/2,2kπ+π）时,g(x)单调减
∴单调减区间：（kπ-π/3,kπ-π/12）,（kπ+π/6,kπ+5π/12）