4(x-0.123)+7(y+3.45)=1 5(x-0.123)-(y+3.45)=11用代入法求二元一次方程组(需过程)
问题描述:
4(x-0.123)+7(y+3.45)=1 5(x-0.123)-(y+3.45)=11用代入法求二元一次方程组(需过程)
答
{4(X-0.123)+7(Y+3.45)=1{5(x-0.123)-(y+3.45)=11
4(X-0.123)+7(Y+3.45)=1
5(x-0.123)-(y+3.45)=11
解得
x=2.123
y=-4.45