关于分式加减道应用题
问题描述:
关于分式加减道应用题
先化简,再求值:x/(x-y)·(x^2-y^2)/(x+y)+(2y+2)/(x-y),其中x,y满足方程组:
x+2y=3
{
x-y=-2
答
原式=X(x^2-y^2)/(X-Y)(X+y)+(2y+2)/(x-y)
=X+(2y+2)/(x-y)
=X+(2y+2)/-2
=X-Y-1
=-3