Every polynomial with complex coefficients of degree n has n zeros.Find all of the solutions to the equation:(x-2)
问题描述：
Every polynomial with complex coefficients of degree n has n zeros.Find all of the solutions to the equation:(x-2)(x-3)(x-4)(x-5) = 360
答
求(x-2)(x-3)(x-4)(x-5) = 360的根
360=3x4x5x6=(-3)(-4)(-5)(-6)
所以解是x=8 or x=-1
另外两个根是x^2-7x+30=0的复数根
所以,按照题意可求得的解是
x1=8 x2=-1