e^(xy)+tan(xy)=y,求dy
问题描述：
e^(xy)+tan(xy)=y,求dy
答
e^(xy)+tan(xy)=y,求dy作函数F(x,y)=y-e^(xy)-tan(xy)=0则dy/dx=-(∂F/∂x)/(∂F/∂y)=-[-ye^(xy)-ysec²(xy)]/[1-xe^(xy)-xsec²(xy)]故dy={[ye^(xy)+ysec²(xy)]/[(1-xe^(xy)-xse...